A ball of mass 0.2kg strikes an obstacle and moves 60 degree to its original direction If its speed aslo changes from 20m/s to 10m/s the magnitude of the impulse received by ball is
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52
Given,
mass = 0.2 kg,
u = 20 m/s,
v = 10 m/s,
theta = 60 degrees
Initial momentum (Pi) = 0.2 x 20 = 4
Final momentum (Pf) = 0.2 x 10 = 2
We know that,
magnitude of impulse =
under root (Pi)^2 + (Pf)^2 - 2 x Pf x Pi x cos 60
= 4 + 16 - 8
= 12
Thus, the magnitude of impulse = 12 kg m/ S.
mass = 0.2 kg,
u = 20 m/s,
v = 10 m/s,
theta = 60 degrees
Initial momentum (Pi) = 0.2 x 20 = 4
Final momentum (Pf) = 0.2 x 10 = 2
We know that,
magnitude of impulse =
under root (Pi)^2 + (Pf)^2 - 2 x Pf x Pi x cos 60
= 4 + 16 - 8
= 12
Thus, the magnitude of impulse = 12 kg m/ S.
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22
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