A ball of mass 0.5 kg is dropped from a height. find the work done by its weight in one seconds after the ball is dropped.
Answers
Answered by
6
m = 5/10kg
u = 0
g = 9.8m/s square
t = 1sec
F = mg
= 5/10×98/10
= 49/10N
Since,
S = ut + 1/2 at square
= 0×1 + 1/2×98/10×1×1
= 49/10m
Since,
W = Fs
= 49/10×49/10j
----------
Hope it helps u
Please thumbs up! !!!!
u = 0
g = 9.8m/s square
t = 1sec
F = mg
= 5/10×98/10
= 49/10N
Since,
S = ut + 1/2 at square
= 0×1 + 1/2×98/10×1×1
= 49/10m
Since,
W = Fs
= 49/10×49/10j
----------
Hope it helps u
Please thumbs up! !!!!
shubham495:
thanks you are excellent
Similar questions