Question

A ball of mass 0.5 kg is thrown up with a velocity of 15 metre per second find its potential energy at the highest point take g=10 metre per second square​

Answer 1

Answer:

The potential energy at the highest point is 56.25 J

Explanation:

Mass of the ball = 0.5 kg

Initial velocity, u = 15 m/s

Maximum height reached by the ball  ,

                      $h = \frac{u^{2} }{2g} = \frac{15^{2} }{2\times10} = 11.25 m$

Potential energy at the highest point ,

                      PE = m×g×h

                          where, m → mass of the object

                                       g  → acceleration due to gravity

                                       h → maximum height reached by the object

                    PE = 0.5 × 10 × 11.25 = 56.25 J