Question

A ball of mass 1 kg hangs in equilirbium from
two strings OA and OB as shown in figure.
What are the tensions in strings OA and OB ?
(Take g = 10 ms-2​

Answer 1

Explanation:

may ittttttttt help you

Answer 2

ANSWER:

The tension on wire OA and OB is taken as $\mathrm{T}_{1}, \mathrm{T}_{2}=5 \mathrm{N}, 5 \sqrt{3} \mathrm{N}$

EXPLANATION:

The mass of the ball hanging from the two strings is 1 kg, the tension on the strings are taken as $\mathrm{T}_{1}, \mathrm{T}_{2}$

The gravitational force of acceleration is taken as $10 \mathrm{m} / \mathrm{sec}^{2}$

Now taking the strings OA and OB, therefore, the tension of the strings are

 Now using Lami’s Law we get the value of tension holding the ball as  

$\frac{T_{1}}{\sin 120}=\frac{T_{2}}{\sin 150}=\frac{10}{\sin 90}$

$T_{1}=\frac{10 \times \sin 120}{\sin 90}=5 \sqrt{3}$

$T_{2}=\frac{10 \times \sin 150}{\sin 90}=5$

Therefore, the tension on wire OA and OB is taken as $\mathrm{T}_{1}, \mathrm{T}_{2}=5 \mathrm{N}, 5 \sqrt{3} \mathrm{N}$