A ball of mass 1 kg is dropped from a height of 5 m. (a) Find the kinetic energy of the ball just before it reaches the ground (h) What is the speed at this instant?
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Solution
(i) W
gravity
=−mg△h=mg(h
i
−h
f
)
=(1)(10)[5−1/2]=45J
By work - Energy Theorem,
W
net
=△KE
⇒W
gravity
=
2
m
[v
f
2
−v
i
2
]
⇒45=(
2
m
)[v
2
−(0)
2
]
⇒
2
mv
2
=45J
Find KE of the ball is 45J.
(ii)PE=−mgh
=−(1)(10)(1/2)=−5J
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