A ball of mass 1 kg is projected with 10 m/s from the top of a tower of height 20 m .What is its speed when it is at vertical distance of 10 m below point of projection.
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velocity or free fall of the body is independent of it's mass .
using v2 = u2 + 2as
v2 = 100 + 2 x 10 x 10 = √ 300 = 10 √ 3 m/s
using v2 = u2 + 2as
v2 = 100 + 2 x 10 x 10 = √ 300 = 10 √ 3 m/s
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Answer:17.32
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