"a ball of mass 1 kg moves perpendicularly to a bat with a speed of 5 m/s. and the bat of 10 kg moves opposite to the ball with 2 m/s. after hitting ball moved with 15 m/s. what is the speed of bat after hit ?
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Answered by
4
conserve momentum
initial momentum is
10*2-1*5=15
final
15-10v
so
final= initial
15=15-10v
v=0
initial momentum is
10*2-1*5=15
final
15-10v
so
final= initial
15=15-10v
v=0
Answered by
1
Answer:
m1=1kg,m2=10kg,u1=5m/s,u2=2m/s, v1=15m/s,v2=?
Step-by-step explanation:
By conservation of linear momentum,
m1u1+m2u2=m1v1+m2v2
1*5+10*2=1*15+10v2
5+20=15+10v2
25=15+10v2
25-15=10v2
10=10v2
V2=10/10=1m/s
Therefore v2=1m/s
Hope it helps!
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