"a body is projected horizontally with a velocity squrt root of 29 m/s from a height 10 m, the velocity on reaching the ground ---------m/s
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When body reach at h=10 cm then the potential energy of body = mgh
When body is a about to reach the ground, Let it's velocity is V
Then according to conservation of energy
mgh=(mV*square) /2
Putting value we get V= 10 under root 2 m/s
When body is a about to reach the ground, Let it's velocity is V
Then according to conservation of energy
mgh=(mV*square) /2
Putting value we get V= 10 under root 2 m/s
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