Question

A ball of mass 1 kg strikes a wall normally with the speed of 10 m/s and rebound with the speed of 5 m/s in opposite direction. The magnitude of change in momentum of the ball is

Answer 1

Explanation:

m=1kg

u=10m/s

v=5m/s

change in momentum =mv-mu

m(v-u)

1(5-10)

-5 is the answer.....

Answer 2

Answer :

➥ The magnitude of change in momentum of the ball = -5 kg m/s

Given :

➤ Mass of a ball (m) = 1 kg

➤ Intial velocity of a ball (u) = 10 m/s

➤ Final velocity of a ball (v) = 5 m/s

To Find :

➤ Magnitude of change in momentum = ?

Solution :

In the above question given that mass is 1 kg, Intial velocity is 10 m/s and final velocity is 5 m/s. So, $\:$

As we know that

→ Change in momentum = mv - mu

→ Change in momentum = m(v - u)

→ Change in momentum = 1(5 - 10)

→ Change in momentum = 1 × (-5)

→ Change in momentum = -5 kg m/s

Hence, the magnitude of change in momentum is -5 kg m/s.