Question

A ball of mass 10 kg is thrown vertically upward with a velocity of 5 m per second what will be the value of its potential energy when it reaches to maximum height

Answer 1

given
m=10 kg
v=5 m
we want to find height

Answer 2

Answer:125 J

Explanation:

From newton's 3rd law

v^2=u^2 + 2gh

Where v=0(at top) , u=5m/s,g=9.8

h=u^2/2g =25/2×9.8

P.E=mgh = 10×9.8×25/2×9.8=125J