A ball of mass 10 kg moving with velocity 20 m/s collides elastically with wall and rebound with the same speed. Then the magnitude of change in momentum of the ball will be :
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A ball of mass 10kg moving with velocity 20m/s collided elastically with the wall and rebound with the same speed .
so, initial momentum of the ball = mv
= 10kg × 20 m/s = 200 kgm/s
final momentum of the ball = m(-v)
[ here negative sign shows that velocity of ball is just opposite direction of its initial motion.]
so, final momentum of the ball = -10 × 20 = -200 kgm/s
hence, change in momentum = final momentum - initial momentum
= -200 - 200 = - 400 kgm/s
hence, magnitude of change in momentum of the ball is 400 kgm/s
so, initial momentum of the ball = mv
= 10kg × 20 m/s = 200 kgm/s
final momentum of the ball = m(-v)
[ here negative sign shows that velocity of ball is just opposite direction of its initial motion.]
so, final momentum of the ball = -10 × 20 = -200 kgm/s
hence, change in momentum = final momentum - initial momentum
= -200 - 200 = - 400 kgm/s
hence, magnitude of change in momentum of the ball is 400 kgm/s
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Answer:
A ball of mass 10kg moving with velocity 20m/s collided elastically with the wall and rebound with the same speed .
so, initial momentum of the ball = mv
= 10kg × 20 m/s = 200 kgm/s
final momentum of the ball = m(-v)
[ here negative sign shows that velocity of ball is just opposite direction of its initial motion.]
so, final momentum of the ball = -10 × 20 = -200 kgm/s
hence, change in momentum = final momentum - initial momentum
= -200 - 200 = - 400 kgm/s
hence, magnitude of change in momentum of the ball is 400 kgm/s
Explanation:
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