Question

How many g of dibasic acid (mol.wt 200) should be present in 100ml. Of the aqueous solution to give strength of 0.1N

Answer 1

quivalent wt. of dibasic acid = mol. wt/2 = 200/2 = 100 Strength = 0.1 N, m = ? , V = 100 mL then, m = EVN/1000 = (100 x 100 x 0.1)/1000 = answered this

Equivalent weight of solute = 200/2=100 N= wt. of solute in grams*1000/Equivalent wt. Of solute *volume (ml) 0.1 =wt. Of solute in grams *1000/100*100 Wt. Of solute in grams =0.1*100*100/1000

Answer 2

so here is your answer