Question

a ball of mass 100-gram is dropped from a height of 5m and is rebounds to a height of 25 m calculate its kinetic energy just before impact​

Answer 1

Answer:

As we know that impulsive force is give by

F.t=m(V-U)

now we have to find the velocity before collision with ground

so mgh1=21mv12

v12=2gh1

v1=7m/sec

again the velocity of ball after collision with ground will be

mgh2=21mv22

v22=2gh2

v2=3.50m/sec

hence net velocity "V"=v1+v2=10.53m/sec

so from impulsive force equation we have to put all these value (U=0)

F=tm(V−U)=0.010.1(10.53)=105.3 N

Explanation:

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