Question

A ball of mass 100 gram is released from a height of 50m.After rebound it attains a height of 40m. Find it's P.E at initial and final point

Answer 1

Simply you can apply the following equation ..

P.E=K.E (Potential energy of ball is converted into Kinetic energy when dropped)

mgh=1/2mv^2

Put the respective values ,

M= 8kg

H= 10m