A ball of mass 100g moving with a velocity of 10 m/s is stopped by a boy in 0.25 seconds .Calculate the force applied by the boy to stop
a ball
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f=ma
m=100g/0.1kg
u=10m/s
v=0m/s
t=0.2s
a=v-u/t
a=0-10/0.2
a=50m/s
t=0.1(-50)
F=-5N
or 5N is In opposite direction
m=100g/0.1kg
u=10m/s
v=0m/s
t=0.2s
a=v-u/t
a=0-10/0.2
a=50m/s
t=0.1(-50)
F=-5N
or 5N is In opposite direction
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