Evaluate using suitable identity 997
Answers
Answered by
7
☆Hey Mate!!!☆
I think you have done an error, question must be 997^2
If yes then,
( 1000 - 3 )^2
( a - b )^2 = a^2 - 2ab + b^2
( 1000 - 3 )^2 = 1000^2 - ( 2×1000×3 ) + 3^2
= 1000000 - 6000 + 9
= 1000009 - 6000
= 994009
Hope it helps☺!
I think you have done an error, question must be 997^2
If yes then,
( 1000 - 3 )^2
( a - b )^2 = a^2 - 2ab + b^2
( 1000 - 3 )^2 = 1000^2 - ( 2×1000×3 ) + 3^2
= 1000000 - 6000 + 9
= 1000009 - 6000
= 994009
Hope it helps☺!
Answered by
12
Answer:
using identity(a-b) ^2
Step-by-step explanation:
997^2
(1000-3)^2
10,00,000+9-2×1,000×3
10,00,009-6000
9,94,009
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