a ball of mass 100g moving with a velocity of 10m/s is stopped by a boy in 0.25 sec.calculate the force applied by the boy to stop the ball .
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Answered by
8
F=ma
m=100g or 0.1 kg
u=10m/s
v=0m/s
t=0.2s
a=v-u/t
a=0-10/0.2
a==50m/s
F=ma
F=0.1(-50)
F=-5N
or 5N opposite to ball
m=100g or 0.1 kg
u=10m/s
v=0m/s
t=0.2s
a=v-u/t
a=0-10/0.2
a==50m/s
F=ma
F=0.1(-50)
F=-5N
or 5N opposite to ball
Answered by
8
The answer is force is = - 4N //
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