Question

a ball of mass 100gm moving with a vilocity of 10m/sec is stopped by a boy in 0.25sec. calculate the force applied by the boy to stop the ball​

Answer 1

Answer:

F=4N

Explanation:

m=100/1000kg v=10m/s t=0.25sec

F=ma

F=mv/t

F=0.1×10/0.25

F=1/0.25

F=4N

Answer 2

Answer:

-4 N

Explanation:

here,

mass of ball = 100 g or 0.1 kg

velocity of ball (u) = 10 m/s

time taken to stop ball (t) = 0.25 sec

Now, force = mass x acceleration = ma

but a is not given, so

a = ( final velocity - initial velocity )/time

= (v - u) /t

= 0 - 10 / 0.25        <=== v = 0 as ball comes to rest

= -10 / 0.25 = -1000 / 25 = -40 m/s^2

so force = ma = 0.1 x -40 = -4 Newtons