Question

A Ball of mass 100kg collides with a wall while moving with a horizontal velocity of 10m/s and return with velocity 8m/s if the collision time is 0.1s then find average impulsive force exerted by the wall on the ball and coefficient of restitution of the collision

Answer 1

Explanation:

1) impulse= change in momentum

P initial= 100×10=1000

P after = 100 × (-8)= -800 ( in opposite direction)

change = 200

2) e= V2-V1/U1-U2= 0-(-8)/10-0 =0.8