A ball of mass 2 KG is dropped from 80 m above earth surface after collision it rebounce and reaches to the same height if the duration of pollution is 0.02 seconds find the force applied by the earth surface all the phone
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Answer:
4000 N
Explanation:
A ball of mass 2 kg is dropped from 80 m above earth. Its final velocity going down is:
Final velocity:
v²= -2gh
= -20(80)= -1600m/s
√v = 40m/s (In downward direction)
Earth must send it back with same velocity.
Change in momentum at impact=
80-(-80)=160 kg-m/s
Time of impact= 0.02s
F=Δp/t=80/0.02=16000/2
=8000 Newtons
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