Question

a ball of mass 2 kg moving with initial velocity 5ms is hit in the direction of initial velocity by a bal for 0.1s the ball velocity becomes 6ms what is the acceleration of the ball​

Answer 1

Answer:

20 newton

Explanation:

a= (v-u)/t

u=5m/s v=6m/s t=0.1s

a= (6-5)/0.1

a=1/0.1 a=10m/s^2

change in momentum =mv-mu =m(v-u)

2(6-5)

2*1=2kgm/s^2

rate of change of momentum =force applied

2/0.1= 20kgm/s^2

(or) F=ma

F=2*10

F=20N