Question

A ball of mass 20 gram hits a wall at an angle of 45 degree with a velocity of 15 M per second if the ball rebounds at 90 degree to the direction of incidence calculate the impulse received by the ball

Answer 1

Impulse = Change in the momentum of the ball

Mass of the ball (m) = 20 gram = 0.02 kg

Velocity = 15 m/s

The component of the velocity which change due to the impact of the wall =  15 Cos 45°

Final velocity = - 15 Cos 45°

Change in momentum = Final momentum - initial momentum

Change in momentum = 0.02 × 2 × 15 Cos 45°

Change in momentum = 0.424 kg m/s

Hence, the impulse provided by the wall is 0.424 kg m/s