A ball of mass 200 g falls from a height of 5 m. When it just reaches the ground, its KE is ____ J (g = 10 m/s2).
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Answered by
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mass of the ball=200g=0.2kg
height=5m
potential energy=mgh
=0.2x5.10
=10J
potential energy=kinetic energy
kinetic energy=10 Joules
hope it helps...
height=5m
potential energy=mgh
=0.2x5.10
=10J
potential energy=kinetic energy
kinetic energy=10 Joules
hope it helps...
Answered by
0
when body released from 5m height then body initial velocity=0
now use
v^2=u^2+2as
=0 +2 (-10)(-5)=100
now
kinetic energy=1/2mv^2
=1/2 x (200/1000) x 100
=10 j
now use
v^2=u^2+2as
=0 +2 (-10)(-5)=100
now
kinetic energy=1/2mv^2
=1/2 x (200/1000) x 100
=10 j
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