A ball of mass 200 gram fall from a height 5 M what is the kinetic energy when it just reaches the ground assume g=10m/s^2
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given : m= 200gm
h=5m
g=10m/s^2
K.E =1/2×mgh
=1/2×100×10×5
=5000 J
h=5m
g=10m/s^2
K.E =1/2×mgh
=1/2×100×10×5
=5000 J
naaz26:
thanks
but isnt formula of KE is 1/2 mv^2
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