Question

Area and perimeter of rectangle is 128 and 48 find diagonal of rectangle

Answer 1

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Answer 2

Question:

Area and perimeter of rectangle is 128 and 48 find diagonal of rectangle

Given:

• Area of rectangle = 128 cm²

• Perimeter of rectangle=48 cm

To Find:

• Diagonal of the rectangle

Formulas Used :

• P = 2(l+b)

• Diagonal of rectangle = √b²+l²

Solution:

48 = 2(l+b)

48/2 = l+b

l+b = 48/2

l+b= 24

Diagonal of rectangle = √b²+l²

(l+b)²=l² + b² + 2lb

Taken area of rectangle = lb=128cm

24²=l² + b²+ 2 x 128

576 = l² + b² + 256

576-256 = l² + b²

320 = l² + b²

d² = 320

d = √320

= 17.8

Answer:

17.8cm

Therefore the diagonal of the rectangle = 17.8 cm

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