A ball of mass 200 kg falls from a height of 5 metres . What is its kinetic energy when it just reaches the ground?(g=9.8)
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Given,mass=200kg
height= 5m
Now,
v^2=u^2+2gh
v^2=0+2(9.8)×5
v^2=98ms^-1
Therefore,
Kinetic energy of the ball
=1/2×200×98
=9800J
height= 5m
Now,
v^2=u^2+2gh
v^2=0+2(9.8)×5
v^2=98ms^-1
Therefore,
Kinetic energy of the ball
=1/2×200×98
=9800J
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