a ball of mass 200g falls from a height 0f 8cm what momentum is trasferred to the floor
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momentum=mass x height.200 x 8=1600
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due to free fall the body is at constant acceleration
v^2 = 2 gh
= 2* 9.8* 8/100
v= 12.5 m/sq sec
therefore, the final momentum of the body before hitting the ground and which shall be transferred is m×v = .5× 12.5
v^2 = 2 gh
= 2* 9.8* 8/100
v= 12.5 m/sq sec
therefore, the final momentum of the body before hitting the ground and which shall be transferred is m×v = .5× 12.5
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