Question

A ball of mass 200g falls from a height 5 meters. What is the kinetic energy when it reaches the ground (g= 9.8m/s²

Answer 1

initial velocity of the ball = 0

distance travelled = 5m

v^2 - u^2 = 2as

v^2 - 0 = 2 x 9.8 x 5

v^2 = 98

200g = 0.2 kg

kinetic energy = mv^2/2

KE = 0.2 x 98/2

KE = 9.8 J

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Answer 2

initial velocity of the ball = 0

distance travelled = 5 m

v^2 - u^2 = 2 as

v^2 - 0 = 2 x 9.8 x 5

v^2 = 98

200 g = 0.2 kg

kinetic energy = mv^2/2

kinetic energy  = 0.2 x 98/2

kinetic energy=  9.8 J

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