Question

A ball of mass 200g falls from a height of 5m. what will be its kinetic energy when it just reaches the ground ?


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Answer 1

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Here, K.E = P.E = mgh

According to principle of conservation of energy.

= 200 /1000 × 9.8 ×5 = 9.8 joule

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Answer 2

K.E at the lowest point = P.E at the highest point

P.E at the highest point = mgh

$=\frac{200}{1000}$ × 9.5 × 5

= 9.8 J

∴ Kinetic Energy when the ball reaches the ground = 9.8 J

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