A ball of mass 200g is moving with a velocity of 5m/s is stopped 0.5 sec. What is the force exerted on the bally
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f=ma
m=200g
t=0.5s
v=5m/s
u=0m/s
a=v-u/t
a=5-0/0.5
a=5/0.5
a=10m/s^2
f=ma
f=200×10
f=2000N
m=200g
t=0.5s
v=5m/s
u=0m/s
a=v-u/t
a=5-0/0.5
a=5/0.5
a=10m/s^2
f=ma
f=200×10
f=2000N
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