Question

A ball of mass 200g strikes a wall with the velocity of 5m/s and rebounds with the velocity of 2m/s. F nd the change in momentum of the ball

Answer 1

m=200 g

v1= -5 ms^-1

v2= +2 ms^-2  ( rebounds in opposite direction, so velocity becomes positive)

Δ ρ= m * Δ v

Δ ρ= m * (v2-v1)

Δ ρ= 200* (2+5)

Δ ρ = 200* +7

Δ ρ = 1400 g ms-1