Question

please help me fast!!!​

Answer 1

Gɪᴠᴇɴ :-

• In a Right angled ∆ , the lengths of sides containing The right angle are = 20cm & 21 cm.

Tᴏ Fɪɴᴅ :-

• Radius of the circumcircle of the ∆.

Fᴏʀᴍᴜʟᴀ ᴜsᴇᴅ :-

• Pythagoras Theoram..
• Radius of circum-circle of a Right Angled ∆ is Half of its Hypotenuse .

Sᴏʟᴜᴛɪᴏɴ :-

By Pythagoras Theoram we get :-

→ (Hypotenuse)² = (20)² + (21)²

→ (Hypotenuse)² = 400 + 441

→ (Hypotenuse)² = 841

→ (Hypotenuse)² = (29)²

→ Hypotenuse = 29cm.

Therefore,

→ Radius of circum-circle of a Right Angled ∆ = (1/2) * Hypotenuse .

→ Radius of the circumcircle = (1/2) * 29

→ Radius of the circumcircle = 14.5cm. (Ans.)

Hence, Radius of the circumcircle of the ∆ is 14.5cm.

Answer 2

Aɴꜱᴡᴇʀ

➜ The radius of the circumcircle is 14.5cm

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Gɪᴠᴇɴ

➳ It is a right angled triangle

➳ Length of sides = 20 and 21 cm

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Tᴏ ꜰɪɴᴅ

➤ The radius of the circumcircle of the triangle?

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Sᴛᴇᴘꜱ

✭ So first let's find the hypotenuse of the right angle triangle with the help of the Pythagoras Theorem.

✪ Hypotheses² = Sum of the sides

✪ Hypotenuse² = 20²+21²

✪ Hypotenuse² = 841

✪ Hypotenuse² = √841

✪ Hypotenuse² = 29

☆ So the radius of the circumcircle = ½ × Hypotenuse

☞ Therefore or answer is $\huge\pink{\tt14.5\: cm}$

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