please help me fast!!!
Answers
Gɪᴠᴇɴ :-
- In a Right angled ∆ , the lengths of sides containing The right angle are = 20cm & 21 cm.
Tᴏ Fɪɴᴅ :-
- Radius of the circumcircle of the ∆.
Fᴏʀᴍᴜʟᴀ ᴜsᴇᴅ :-
- Pythagoras Theoram..
- Radius of circum-circle of a Right Angled ∆ is Half of its Hypotenuse .
Sᴏʟᴜᴛɪᴏɴ :-
By Pythagoras Theoram we get :-
→ (Hypotenuse)² = (20)² + (21)²
→ (Hypotenuse)² = 400 + 441
→ (Hypotenuse)² = 841
→ (Hypotenuse)² = (29)²
→ Hypotenuse = 29cm.
Therefore,
→ Radius of circum-circle of a Right Angled ∆ = (1/2) * Hypotenuse .
→ Radius of the circumcircle = (1/2) * 29
→ Radius of the circumcircle = 14.5cm. (Ans.)
Hence, Radius of the circumcircle of the ∆ is 14.5cm.
Aɴꜱᴡᴇʀ
➜ The radius of the circumcircle is 14.5cm
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Gɪᴠᴇɴ
➳ It is a right angled triangle
➳ Length of sides = 20 and 21 cm
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Tᴏ ꜰɪɴᴅ
➤ The radius of the circumcircle of the triangle?
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Sᴛᴇᴘꜱ
✭ So first let's find the hypotenuse of the right angle triangle with the help of the Pythagoras Theorem.
✪ Hypotheses² = Sum of the sides
✪ Hypotenuse² = 20²+21²
✪ Hypotenuse² = 841
✪ Hypotenuse² = √841
✪ Hypotenuse² = 29
☆ So the radius of the circumcircle = ½ × Hypotenuse
☞ Therefore or answer is