Math, asked by sushamaaru, 10 months ago

please help me fast!!!​

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Answered by RvChaudharY50
21

Gɪᴠᴇɴ :-

  • In a Right angled ∆ , the lengths of sides containing The right angle are = 20cm & 21 cm.

Tᴏ Fɪɴᴅ :-

  • Radius of the circumcircle of the ∆.

Fᴏʀᴍᴜʟᴀ ᴜsᴇᴅ :-

  • Pythagoras Theoram..
  • Radius of circum-circle of a Right Angled ∆ is Half of its Hypotenuse .

Sᴏʟᴜᴛɪᴏɴ :-

By Pythagoras Theoram we get :-

(Hypotenuse)² = (20)² + (21)²

→ (Hypotenuse)² = 400 + 441

→ (Hypotenuse)² = 841

→ (Hypotenuse)² = (29)²

→ Hypotenuse = 29cm.

Therefore,

Radius of circum-circle of a Right Angled ∆ = (1/2) * Hypotenuse .

→ Radius of the circumcircle = (1/2) * 29

→ Radius of the circumcircle = 14.5cm. (Ans.)

Hence, Radius of the circumcircle of the is 14.5cm.

Answered by ғɪɴɴвαłσℜ
28

Aɴꜱᴡᴇʀ

➜ The radius of the circumcircle is 14.5cm

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Gɪᴠᴇɴ

➳ It is a right angled triangle

➳ Length of sides = 20 and 21 cm

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Tᴏ ꜰɪɴᴅ

➤ The radius of the circumcircle of the triangle?

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Sᴛᴇᴘꜱ

✭ So first let's find the hypotenuse of the right angle triangle with the help of the Pythagoras Theorem.

✪ Hypotheses² = Sum of the sides

✪ Hypotenuse² = 20²+21²

✪ Hypotenuse² = 841

✪ Hypotenuse² = √841

✪ Hypotenuse² = 29

☆ So the radius of the circumcircle = ½ × Hypotenuse

☞ Therefore or answer is \huge\pink{\tt14.5\: cm}

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