Question

A ball of mass 200kg hits a wall at an angle of 45degree with a velocity of 15m/s if the ball rebounds at 90degree to the direction of incidence calculate the impulse received by the ball

Answer 1

Mass of the ball = 200 kg

Velocity of the ball = 15 m/s

The component of the velocity which will be changed due to the impact from the wall = - 15 Cos 45°

Rebound component will be 15 Cos 45°

Impulse = change in momentum

Initial momentum Perpendicular to the wall = - mv Cos 45°

Final momentum perpendicular to the wall = mv Cos 45°

Impulse = mv Cos 45° - (- mv Cos 45°)

Impulse = 2 × 200 × 15 × Cos 45°

Impulse = 4242.63 kg m/s

Hence, the impulse provided by the wall is 4242.63 kg m/s