Question

A ball of mass 250 g, having initial speed v, moves along a straight path under the action of a constant net force of 8 N. If the ball has speed v after 2.5 s of its journey, then the value of v is?​

Answer 1

Answer:

40 m/s

Explanation:

P = F * t

=10

P=mv

10 = v/4

v=40 m/s

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Answer 2

Question:-

A ball of mass 250 g, having initial speed v, moves along a straight path under the action of a constant net force of 8 N. If the ball has speed v after 2.5 s of its journey, then the value of v is?

Answer:-

It's velocity after 2.5 second = (v+80)m/s

Step - by - step explanation:-

Using formulas:-

• Newton's law , F = m × a

Here ,F is the force , "m" is the mass of ball and "a "is the acceleration.

• Equation of motion

→ final velocity = initial velocity +a×t

Given that:-

• mass of ball (m) = 250 g =0.25 kg
• Force (F) = 8 Newton
• time (t) = 2.5 second

Solution:-

Using Newton 's las

Force = mass × acceleration

Therefore,

$\bf{ </em><em>acceleration</em><em> \: (a) = \frac{</em><em>force</em><em> </em><em>(f)}</em><em>{</em><em>mass</em><em>(m)} } \\ \\ \rightarrow \: \bf{</em>acceleration<em> \: (a) = \frac{8}{0.25} = 32} \: \: \: \frac{m}{ {s}^{2} } \\</em><em> </em><em>$

Now using equation of motion ,

According to the question,

Its initial velocity is v ,

Final velocity is u after 2.5 second .

hence,

final velocity(v) = initial velocity(v) + a× t

→ u = v + 32× 2.5

→ u =( v + 80) m/s

Hence,

The velocity of ball after 2.5 second is [ initial velocity (v) + 80 ] m/s

Hope it helps you.