Question

A ball of mass 250 g, having initial speed v, moves along a straight path under the action of a constant net force of 8 N. If the ball has speed v after 2.5 s of its journey, then the value of v is?​

Answer 1

Answer:

Explanation:

Given t=2.5s,F=8N,m=250g=1/4kg

F=ma

8=a/4 a=32

Answer 2

Answer:

Force = Mass × Acceleration

According to the question,

• Mass = 250 g = 0.25 Kg
• Force = 8 N

⇒ Acceleration = Force / Mass = 8 / 0.25 = 32 m/s²

Hence Acceleration is 32 m/s²

Now given that Initial Velocity is 'v'. Using First Equation of Motion we get,

⇒ v = u + at

⇒ v' = v + 32t

It is given that we are required to find speed v' after 2.5 s. Substituting this in 't' we get,

⇒ v' = v + 32 ( 2.5 )

⇒ v' = v + 80

Thus the required value of Final Speed is Initial Speed + 80 m/s