a ball of mass 2kg is droped from the tower of 80m to a wooden floor and rebound to the same height . Find change in momentum of the ball.
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Answer:
change in momentum will be 160 kgm/s^2
Explanation:
velocity when ball will strike to the floor
then
v=sqrt{2gh}
v=sqrt{2×10×80}
v=40m/s
in downward direction
velocity just after strike will be 40 because
it will attain same height so collision is perfectly elastic
so change in momentum
∆P=mv-(-mv)
∆P=2mv
∆P=2×2×40
=160kgm/s^2
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