Question

A ball of mass 2kg thrown vertically up with a velocity 20 ms-1.
[g=10ms-2

i) find the distance covered by the ball during the first second in the downward journey

I want the answer ​

Answer 1

Answer:

v^2 = u^2 + 2as

as the highest point the final velocity becomes 0 then ATQ

0 = 400 - 2 x 10 x s     (as the motion of particle in upward direction and acceleration due to gravity works in downward direction therefore the negative sign came in the formula)

400 = 20s

20 m is the distance covered by the ball

now in the downward journey the initial velocity will be 0 and we have to calculate the distance covered in 1 st second of the downward journey

therefore,

s = 1/2g(2n - 1)

s = 1/2 x10 (2 x 1 - 1)

s = 5 x 1

s = 5 m

trust me the second part of the question is inconsequential. and you do not need the mass of the body in the questions of kinematics because the kinematics is the study of motion not the cause of the motion.

hope this helps love

have a wonderful night