A ball of mass 4 kg moving at 6 m/s collides with another ball of mass 6 kg moving at 4 m/s in the same direction. If the balls move together after the collision in the same direction, find their common velocity.
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Answered by
3
Explanation:
Linear momentum is conserved
0.4×4+0.4×2=0.8×v
as shown in figure and B.
v=0.8
1.6+0.8 =3m/sKinetic energy before collision = 2
1 0.4(4) 2 + 2
1 0.4(2)
2=3.2+0.8=4J
Kinetic after collision = 21 0.8(v) 2 =0.8×3 2
=3.6
Loss of kinetic energy =4−3.6=0.4J
Answered by
1
Explanation:
Linear momentum is conserved
0.4×4+0.4×2=0.8×v
as shown in figure and B.
v=0.8
1.6+0.8 =3m/sKinetic energy before collision = 2
1 0.4(4) 2 + 2
1 0.4(2)
2=3.2+0.8=4J
Kinetic after collision = 21 0.8(v) 2 =0.8×3 2
=3.6
Loss of kinetic energy =4−3.6=0.4J
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