A ball of mass 5 kg is dropped from a height of 10 m find initial potential energy of Ball and kinetic energy just before it reaches the ground
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the initial potential energy= mgh
ie. 10x5x9.8(or 10)=500J
ie. 10x5x9.8(or 10)=500J
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3
given that
m= 5 kg
h= 10 m
Ep= mgh
. = 5 x 9.8 x 10
. = 490 j
Ek= 1/2 mv^2
. =0
m= 5 kg
h= 10 m
Ep= mgh
. = 5 x 9.8 x 10
. = 490 j
Ek= 1/2 mv^2
. =0
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