a ball of mass 50 g falls from a height of 20 m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 200 N so that it attains a vertical height of 45 m. The time for which the ball remains in contact with the bat is
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Velocity of ball when it falls from height of 20m
u = sqrt(2gH)
= sqrt(2 * 10 * 20)
= 20 m/s
Velocity of ball with which it’s hitted by bat
v = sqrt(2gH)
= sqrt(2 * 10 * 45)
= 30 m/s
F = m * (v - u) / t
t = m * (v - u) / F
= 50 * 10^-3 * (30 - 20) / 200
= 0.0025 seconds
= 2.5 milliseconds
Ball remains in contact with bat for 2.5 milliseconds
u = sqrt(2gH)
= sqrt(2 * 10 * 20)
= 20 m/s
Velocity of ball with which it’s hitted by bat
v = sqrt(2gH)
= sqrt(2 * 10 * 45)
= 30 m/s
F = m * (v - u) / t
t = m * (v - u) / F
= 50 * 10^-3 * (30 - 20) / 200
= 0.0025 seconds
= 2.5 milliseconds
Ball remains in contact with bat for 2.5 milliseconds
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