A ball of mass 50g is dropped from a height 20m A boy on the ground hit the Ball vertically upward with a bat
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Answer:
u1= velocity up = 0
V1= velocity before hitting bat
s1= distance before hitting bat
v1^2 = u1^2 + 2as
v1^2 = 0+ 2*10*45
V1= 20 m/s
F=M*A
A= 200/ 50*10^-3
=4000
U2 = velocity after hitting bat
V2= velocity at top = 0
s2 = distance covered after hitting bat = 45
u2^2= -2*10*45
u2= -30
time :
-30= 20 - 4000*t
t= (-30–20/-4000)
= 1/80th of a second
Explanation:
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