A ball of mass 50g is thrown upwards . if rises to a maximum height of 100m. its K.E. reduced to 70% at height 10xn meter . Find the value of n?
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Answered by
10
H= u²/2g
H=u²/2g - v²/2g
=0,3u²/2g
=30 m
H=u²/2g - v²/2g
=0,3u²/2g
=30 m
Answered by
23
total energy will be conserved and here total energy is
mgh=0.005*10*100=50J
and 70 of K.E is 35 J
so
mgx+70% K.E = 50
it implie
s mgx =50-35 i.e.
x=30m
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