a ball of mass 5kg is dropped from a height of 78.4m .the time taken by the ball to hit the ground is :-
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9
use
h = 1/2gt^2
t = √78.4*2/9.8 = 4 sec
h = 1/2gt^2
t = √78.4*2/9.8 = 4 sec
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Answered by
12
distance=1/2att
78.4=1/2×9.8×t2
t2=78.4÷4.9
t=√16=4sec.
78.4=1/2×9.8×t2
t2=78.4÷4.9
t=√16=4sec.
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