the numerator of a rational number is less than its denominator by 3 if the numerator becomes three times and the denominator is increased by 20 the new number become 1 by 8 find the original number
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the numerator of a rational number is less than its denominator by 3.if the numerator became 3 times and the denominator is increased by 20,the faction became 1\8,find the original faction
.
Let d = denominator
then
d-3 = numerator
.
3(d-3)/(d+20) = 1/8
(3d-9)/(d+20) = 1/8
cross multiplying:
8(3d-9) = (d+20)
24d-72 = d+20
23d-72 = 20
23d = 92
d = 4 (denominator)
.
numerator:
d-3 = 4-3 = 1
.
answer: 1/4
over and out.....
plz mark as brainiest.... :)
.
Let d = denominator
then
d-3 = numerator
.
3(d-3)/(d+20) = 1/8
(3d-9)/(d+20) = 1/8
cross multiplying:
8(3d-9) = (d+20)
24d-72 = d+20
23d-72 = 20
23d = 92
d = 4 (denominator)
.
numerator:
d-3 = 4-3 = 1
.
answer: 1/4
over and out.....
plz mark as brainiest.... :)
seedha19:
thx
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