A car moving with a speed of 50 km per hour can we stop by break after at least 6 km if the car is moving at a speed of 100 km per hour the minimum stopping distance is
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3km is the answer .
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Solution :
Initial velocity :50km/hr=50∗5/18:50km/hr=50∗5/18(convert to m/s)=250/18=250/18m/s
Final velocity(v)=0m/s(v)=0m/sDistance=6m=6m
using formula v2=U2+2aS,v2=U2+2aS, we can calculate acceleration.a=−u2/2sa=−16.075m/sSq.a=−u2/2sa=−16.075m/sSq.Now again,v2=U2+2aS,v2=U2+2aS
02=(100∗5/18)2+2∗(−16.075)∗s02=(100∗5/18)2+2∗(−16.075)∗s
s=24ms=24m
Over and out .
plz mark as brainiest..... :)
Initial velocity :50km/hr=50∗5/18:50km/hr=50∗5/18(convert to m/s)=250/18=250/18m/s
Final velocity(v)=0m/s(v)=0m/sDistance=6m=6m
using formula v2=U2+2aS,v2=U2+2aS, we can calculate acceleration.a=−u2/2sa=−16.075m/sSq.a=−u2/2sa=−16.075m/sSq.Now again,v2=U2+2aS,v2=U2+2aS
02=(100∗5/18)2+2∗(−16.075)∗s02=(100∗5/18)2+2∗(−16.075)∗s
s=24ms=24m
Over and out .
plz mark as brainiest..... :)
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