A ball of mass 7.00 kg is hung by two cables attached to the walls as shown in the followingfigure. Calculate the tension in the horizontal cable352(a) 48.0 N(b) 83.5 N(c) 68.6 N(d) 93.5 N
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Thus the tension in horizontal cable is 76 N
Explanation:
Given data:
- Mass "m" = 7.0 Kg
- g = 9.8 m/ s^2
- Angle "θ" = 35°
Solution:
T1 cosθ - mg = 0
T cosθ = mg
T = mg / cosθ
T = 7 x 9.8 / cos (35°)
T = 68.6 / - 0.903
T = 75.96 ~ 76 N
Thus the tension in horizontal cable is 76 N
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Explanation:
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