A ball of mass 70g moving with a speed of 0.5m/s is stopped by a player in 0.05 second calculate the force exerted by the player
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Acceleration of ball is
a = (v - u) / t
= (0 - 0.5) / 0.05
= -10 m/s²
Force from Newton’s second law is
F = ma
= 0.07 kg × (-10 m/s²)
= -0.7 N
Why negative sign?
Because force on ball is in the opposite direction of motion ball. Obviously that’s how a ball can be stoppped.
a = (v - u) / t
= (0 - 0.5) / 0.05
= -10 m/s²
Force from Newton’s second law is
F = ma
= 0.07 kg × (-10 m/s²)
= -0.7 N
Why negative sign?
Because force on ball is in the opposite direction of motion ball. Obviously that’s how a ball can be stoppped.
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