Question

A ball of mass M is dropped from height H on a horizontal floor which collides with it with speed U if coefficient of resistance in flores is an impulse imparted to ball by the floor and its second rebounds is

Answer 1

Answer:

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Answer 2

Explanation:

A ball fall on floor with velocity u. Coefficient of restitution is e. The velocity after first bounce is eu and velocity after a second bounce is ex, eu

which is equal to $e^{2} u$.  

Momentum after first bounce is meu and momentum after second bounce is

$-m e^{2} u$. So, the change in momentum is

$Meu- \left(-m e^{2} u\right)$

$Meu (1+e)$, where u is the initial velocity.

This is independent on height h.