Question

a ball of mass m is dropped from height h. what is the motion of the ball​

Answer 1

Explanation:

The particle is dropped from height h and the spring be compressed by x.

Loss in PE of the particle = gain in elastic PE of the spring

${ \tt{mg(h+x)= \frac{1}{2} kx {}^{2} }}$

${ \tt{⇒k= \frac{2mg(h+x)}{x²} }}$

@ItzMaira

Answer 2

Explanation:

please follow me

. and mark my answer