a ball of mass m is moving with velocity v. it strikes the floor and rebounds with same velocity . if n such balls strike the floor per sec then force exerted by the balls on floor is
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Answer:
F=2nmu
Explanation:
change in momentum is - 2mu but the momentum is conserved in the collision so it will be 2mu.
the number of ball per sec is n & as per Newton's 2nd law force = rate of change momentum.so
the force exerted by the ball on floor = 2mu×n/ 1sec
= 2nmu
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